What is (-8m^2+8m-2)/(32m^2-4m-6) ?

The solution to (-8m^2+8m-2)/(32m^2-4m-6) is -(2m-1)/(8m+3)

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simplify (-8m^2+8m-2)/(32m^2-4m-6)

simplify

\frac{- 8 m ^{2} + 8 m - 2}{32 m ^{2} - 4 m - 6}

- \frac{2 m - 1}{8 m + 3}

Solution steps

\frac{- 8 m ^{2} + 8 m - 2}{32 m ^{2} - 4 m - 6}

Factor

- 8 m^{2} + 8 m - 2 : - 2 (2 m - 1)^{2}

= \frac{- 2 ( 2 m - 1 ) ^{2}}{32 m ^{2} - 4 m - 6}

Factor

32 m^{2} - 4 m - 6 : 2 (8 m + 3) (2 m - 1)

= \frac{- 2 ( 2 m - 1 ) ^{2}}{2 ( 8 m + 3 ) ( 2 m - 1 )}

Cancel the common factor:

2

= \frac{- ( 2 m - 1 ) ^{2}}{( 8 m + 3 ) ( 2 m - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(2 m - 1)^{2} = (2 m - 1) (2 m - 1)

= \frac{- ( 2 m - 1 ) ( 2 m - 1 )}{( 8 m + 3 ) ( 2 m - 1 )}

Cancel the common factor:

2 m - 1

= \frac{- ( 2 m - 1 )}{8 m + 3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2 m - 1}{8 m + 3}

- (\frac{2}{3})^{3}

4 f^{2} - 64

(a^{2} + 1)^{2} - 7 (a^{2} + 1) + 10

(\frac{1}{6})^{\frac{1}{4}}

10 (a + 1) = 20

What is (-8m^2+8m-2)/(32m^2-4m-6) ?
The solution to (-8m^2+8m-2)/(32m^2-4m-6) is -(2m-1)/(8m+3)