What are the solutions to the equation 3x^2-7x-1=0 ?

The solutions to the equation 3x^2-7x-1=0 are x=(7+sqrt(61))/6 ,x=(7-sqrt(61))/6

Find the zeros of 3x^2-7x-1=0

The zeros of 3x^2-7x-1=0 are x=(7+sqrt(61))/6 ,x=(7-sqrt(61))/6

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3 x^{2} - 7 x - 1 = 0

x = \frac{7 + 61}{6}, x = \frac{7 - 61}{6}

Decimal Notation

x = 2.46837 \dots, x = - 0.13504 \dots

Solution steps

3 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 1) = 61

x_{1, 2} = \frac{- ( - 7 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 61}{2 \cdot 3}

x = \frac{- ( - 7 ) + 61}{2 \cdot 3} : \frac{7 + 61}{6}

x = \frac{- ( - 7 ) - 61}{2 \cdot 3} : \frac{7 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 61}{6}, x = \frac{7 - 61}{6}

\frac{0}{10}

x^{2} - 2 x - 1 < 0

\frac{x ^{11}}{x ^{11}}

x + 4 < - 1 or x + 3 \geq 2

What are the solutions to the equation 3x^2-7x-1=0 ?
The solutions to the equation 3x^2-7x-1=0 are x=(7+sqrt(61))/6 ,x=(7-sqrt(61))/6
Find the zeros of 3x^2-7x-1=0
The zeros of 3x^2-7x-1=0 are x=(7+sqrt(61))/6 ,x=(7-sqrt(61))/6