What are the solutions to the equation 32=704+16t-16t^2 ?

The solutions to the equation 32=704+16t-16t^2 are t=-6,t=7

Find the zeros of 32=704+16t-16t^2

The zeros of 32=704+16t-16t^2 are t=-6,t=7

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32 = 704 + 16 t - 16 t^{2}

t = - 6, t = 7

Solution steps

32 = 704 + 16 t - 16 t^{2}

Switch sides

704 + 16 t - 16 t^{2} = 32

Move

32

to the left side

- 16 t^{2} + 16 t + 672 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 672}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 672 = 208

t_{1, 2} = \frac{- 16 \pm 208}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 208}{2 ( - 16 )}, t_{2} = \frac{- 16 - 208}{2 ( - 16 )}

t = \frac{- 16 + 208}{2 ( - 16 )} : - 6

t = \frac{- 16 - 208}{2 ( - 16 )} : 7

The solutions to the quadratic equation are:

t = - 6, t = 7

\frac{1}{y} < 1

(- 18 m^{2} n)^{2} (- \frac{1}{6} m n^{2})

(\frac{64}{25})^{- \frac{1}{2}}

\frac{9 ^{12}}{9 ^{8}}

\frac{( 3 x - 5 )}{2} + \frac{( 8 x - 12 )}{7} = 9

What are the solutions to the equation 32=704+16t-16t^2 ?
The solutions to the equation 32=704+16t-16t^2 are t=-6,t=7
Find the zeros of 32=704+16t-16t^2
The zeros of 32=704+16t-16t^2 are t=-6,t=7