What is (1/3+4/3 i)-(2/3+8/3 i) ?

The solution to (1/3+4/3 i)-(2/3+8/3 i) is -1/3-4/3 i

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simplify (1/3+4/3 i)-(2/3+8/3 i)

simplify

(\frac{1}{3} + \frac{4}{3} i) - (\frac{2}{3} + \frac{8}{3} i)

- \frac{1}{3} - \frac{4}{3} i

Solution steps

(\frac{1}{3} + \frac{4}{3} i) - (\frac{2}{3} + \frac{8}{3} i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (\frac{1}{3} - \frac{2}{3}) + (\frac{4}{3} - \frac{8}{3}) i

Simplify

(\frac{1}{3} - \frac{2}{3}) + (\frac{4}{3} - \frac{8}{3}) i : - \frac{1}{3} - \frac{4}{3} i

= - \frac{1}{3} - \frac{4}{3} i

∣ 5 x + 6 ∣ + 6 = 2 x

(2 x - 1)^{- 1} > 0

\frac{( x + 1 )}{2} + 4 \leq 6 + x

2 r^{7} t^{7} - 4 r^{8} t^{6}

2 X + 4 > 10

What is (1/3+4/3 i)-(2/3+8/3 i) ?
The solution to (1/3+4/3 i)-(2/3+8/3 i) is -1/3-4/3 i