What are the solutions to the equation (x-3)(2x+1)=0 ?

The solutions to the equation (x-3)(2x+1)=0 are x=3,x=-1/2

Find the zeros of (x-3)(2x+1)=0

The zeros of (x-3)(2x+1)=0 are x=3,x=-1/2

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(x - 3) (2 x + 1) = 0

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

(x - 3) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 2 x + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

∣ x - 1 ∣ + ∣ x + 3 ∣ = 4

7 f - 3 \leq 4 f + 6

(- 27)^{\frac{1}{3}}

16 - 7

x^{2} = 500

What are the solutions to the equation (x-3)(2x+1)=0 ?
The solutions to the equation (x-3)(2x+1)=0 are x=3,x=-1/2
Find the zeros of (x-3)(2x+1)=0
The zeros of (x-3)(2x+1)=0 are x=3,x=-1/2