What is |4x+5|>= x+11 ?

The solution to |4x+5|>= x+11 is x = 2

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|4x+5|>= x+11

∣ 4 x + 5 ∣ \geq x + 11

x \leq - \frac{16}{5} or x \geq 2

Interval Notation

(- \infty, - \frac{16}{5}] \cup [2, \infty)

Decimal Notation

x \leq - 3.2 or x \geq 2

Solution steps

∣ 4 x + 5 ∣ \geq x + 11

Find positive and negative intervals

x < - \frac{5}{4}, x \geq - \frac{5}{4}

Solve the inequality for each interval

x \leq - \frac{16}{5} or x \geq 2

(2 x)^{2}

a^{12} x^{4} - a^{4} x^{12}

- 2 x^{2} + 50 = 2

(\frac{a}{b})^{- 3} \cdot (a^{- 1})^{- 2}

(5 x^{3} y^{2})^{3}