What is (5x-3)/(x^2-25)<= 0 ?

The solution to (5x-3)/(x^2-25)<= 0 is x<-5\lor 3/5 <= x<5

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(5x-3)/(x^2-25)<= 0

\frac{5 x - 3}{x ^{2} - 25} \leq 0

x < - 5 or \frac{3}{5} \leq x < 5

Interval Notation

(- \infty, - 5) \cup [\frac{3}{5}, 5)

Decimal Notation

x < - 5 or 0.6 \leq x < 5

Solution steps

\frac{5 x - 3}{x ^{2} - 25} \leq 0

Factor

\frac{5 x - 3}{x ^{2} - 25} : \frac{5 x - 3}{( x + 5 ) ( x - 5 )}

\frac{5 x - 3}{( x + 5 ) ( x - 5 )} \leq 0

Identify the intervals

x < - 5 or \frac{3}{5} \leq x < 5

3 (x - 4) (x - 5) = 0

x^{3} (6 x^{2} + x) \geq 2 x^{3}

12 (5 + 2 y) = 4 y - (5 - 9 y)

5^{\frac{1}{2}} \cdot 5^{\frac{1}{2}}

x m + y m + x n + y n

What is (5x-3)/(x^2-25)<= 0 ?
The solution to (5x-3)/(x^2-25)<= 0 is x<-5\lor 3/5 <= x<5