What are the solutions to the equation 4x^2+9=15 ?

The solutions to the equation 4x^2+9=15 are x=sqrt(3/2),x=-sqrt(3/2)

Find the zeros of 4x^2+9=15

The zeros of 4x^2+9=15 are x=sqrt(3/2),x=-sqrt(3/2)

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4 x^{2} + 9 = 15

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.22474 \dots, x = - 1.22474 \dots

Solution steps

4 x^{2} + 9 = 15

Move

9

to the right side

4 x^{2} = 6

Divide both sides by

4

x^{2} = \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{2}, x = - \frac{3}{2}

49 x^{2} - 70 x + 25

3 x^{2} + 18 x + 27

x \geq 2 and x \leq 8

\frac{( 2 + 5 i )}{( 3 - 2 i )}

\frac{x ^{2} + 4 x - 1}{( x ^{2} + 1 ) ( x + 2 )} > 0

What are the solutions to the equation 4x^2+9=15 ?
The solutions to the equation 4x^2+9=15 are x=sqrt(3/2),x=-sqrt(3/2)
Find the zeros of 4x^2+9=15
The zeros of 4x^2+9=15 are x=sqrt(3/2),x=-sqrt(3/2)