What is the answer to ((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0 ?

The answer to ((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0 is x= 1/4

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((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0

\frac{( 2 x - 3 )}{6} - 2 (\frac{3}{2} x - 1) - \frac{3 - 2 x}{3} = 0

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

\frac{( 2 x - 3 )}{6} - 2 (\frac{3}{2} x - 1) - \frac{3 - 2 x}{3} = 0

\frac{2 x - 3}{6} - 2 (\frac{3}{2} x - 1) - \frac{3 - 2 x}{3} = 0

Multiply by LCM

2 x - 3 - 12 (\frac{3}{2} x - 1) - 2 (- 2 x + 3) = 0

Expand

2 x - 3 - 12 (\frac{3}{2} x - 1) - 2 (- 2 x + 3) : - 12 x + 3

- 12 x + 3 = 0

Move

3

to the right side

- 12 x = - 3

Divide both sides by

- 12

x = \frac{1}{4}

- 45 x^{8} y^{2} z^{4} - 18 x^{4} y^{6} z^{7}

3 x + 1 = 8 x - 24

m + 14 = 81

\frac{2 \cdot 5}{2}

(x - 1)^{2} - (x + 2)^{2} + 3 x^{2} \leq - 7 x + 1

What is the answer to ((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0 ?
The answer to ((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0 is x= 1/4
Solve for x: ((2x-3))/6-2(3/2 x-1)-(3-2x)/3 =0
The solution is x= 1/4