What are the solutions to the equation 0=x^2-4x+7 ?

The solutions to the equation 0=x^2-4x+7 are x=2+sqrt(3)i,x=2-sqrt(3)i

Find the zeros of 0=x^2-4x+7

The zeros of 0=x^2-4x+7 are x=2+sqrt(3)i,x=2-sqrt(3)i

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0 = x^{2} - 4 x + 7

x = 2 + 3 i, x = 2 - 3 i

Solution steps

0 = x^{2} - 4 x + 7

Switch sides

x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 7 : 23 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1} : 2 + 3 i

x = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1} : 2 - 3 i

The solutions to the quadratic equation are:

x = 2 + 3 i, x = 2 - 3 i

- 5 x + 9 < - 3 x - 11

e^{- 2 x}

4 a > - 20 and 3 a - 2 < 7

(54 y)^{\frac{2}{3}}

What are the solutions to the equation 0=x^2-4x+7 ?
The solutions to the equation 0=x^2-4x+7 are x=2+sqrt(3)i,x=2-sqrt(3)i
Find the zeros of 0=x^2-4x+7
The zeros of 0=x^2-4x+7 are x=2+sqrt(3)i,x=2-sqrt(3)i