What are the solutions to the equation x^2-14x+43=0 ?

The solutions to the equation x^2-14x+43=0 are x=7+sqrt(6),x=7-sqrt(6)

Find the zeros of x^2-14x+43=0

The zeros of x^2-14x+43=0 are x=7+sqrt(6),x=7-sqrt(6)

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x^{2} - 14 x + 43 = 0

x = 7 + 6, x = 7 - 6

Decimal Notation

x = 9.44948 \dots, x = 4.55051 \dots

Solution steps

x^{2} - 14 x + 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 43}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 43 = 26

x_{1, 2} = \frac{- ( - 14 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 6}{2 \cdot 1} : 7 + 6

x = \frac{- ( - 14 ) - 2 6}{2 \cdot 1} : 7 - 6

The solutions to the quadratic equation are:

x = 7 + 6, x = 7 - 6

t^{2} - 9 t + 10 = 0

x^{2} - 3 x \leq 18

(- 2 x)^{- 2}

t = - \frac{ln ( 2 )}{ln ( \frac{298}{500} )} \cdot 8

a^{2} - 3 a

What are the solutions to the equation x^2-14x+43=0 ?
The solutions to the equation x^2-14x+43=0 are x=7+sqrt(6),x=7-sqrt(6)
Find the zeros of x^2-14x+43=0
The zeros of x^2-14x+43=0 are x=7+sqrt(6),x=7-sqrt(6)