What is factor 16n^2+8n+1 ?

The solution to factor 16n^2+8n+1 is (4n+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 16n^2+8n+1

factor

16 n^{2} + 8 n + 1

(4 n + 1)^{2}

Solution steps

16 n^{2} + 8 n + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 n^{2} = (4 n)^{2}

1 = 1^{2}

8 n = 2 \cdot 4 n \cdot 1

= (4 n)^{2} + 2 \cdot 4 n \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(4 n)^{2} + 2 \cdot 4 n \cdot 1 + 1^{2} = (4 n + 1)^{2}

= (4 n + 1)^{2}

\frac{17}{6} - \frac{125}{6} + \frac{17}{6}

- \frac{1}{2} \cdot 1

x < 5 and x > - 1

\frac{3}{4} \cdot \frac{1}{6}

7 \leq 4 x + 5 < 13