What are the solutions to the equation -3+16x-5x^2=0 ?

The solutions to the equation -3+16x-5x^2=0 are x= 1/5 ,x=3

Find the zeros of -3+16x-5x^2=0

The zeros of -3+16x-5x^2=0 are x= 1/5 ,x=3

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- 3 + 16 x - 5 x^{2} = 0

x = \frac{1}{5}, x = 3

Decimal Notation

x = 0.2, x = 3

Solution steps

- 3 + 16 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 16 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 5 ) ( - 3 )}{2 ( - 5 )}

1 6^{2} - 4 (- 5) (- 3) = 14

x_{1, 2} = \frac{- 16 \pm 14}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 16 + 14}{2 ( - 5 )}, x_{2} = \frac{- 16 - 14}{2 ( - 5 )}

x = \frac{- 16 + 14}{2 ( - 5 )} : \frac{1}{5}

x = \frac{- 16 - 14}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = 3

1 - 3 x^{2} = 0

\frac{4 x - 1}{x} > 0

\frac{a + 1}{a - 2} > 3

4 (5)^{4} + 24 (5)^{\frac{1}{3}}

\frac{1}{3} 21 - 1 - \frac{1}{2} 12

What are the solutions to the equation -3+16x-5x^2=0 ?
The solutions to the equation -3+16x-5x^2=0 are x= 1/5 ,x=3
Find the zeros of -3+16x-5x^2=0
The zeros of -3+16x-5x^2=0 are x= 1/5 ,x=3