What are the solutions to the equation 25x^2+16=-40x ?

The solutions to the equation 25x^2+16=-40x are x=-4/5

Find the zeros of 25x^2+16=-40x

The zeros of 25x^2+16=-40x are x=-4/5

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25 x^{2} + 16 = - 40 x

x = - \frac{4}{5}

Decimal Notation

x = - 0.8

Solution steps

25 x^{2} + 16 = - 40 x

Move

40 x

to the left side

25 x^{2} + 16 + 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} + 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

4 0^{2} - 4 \cdot 25 \cdot 16 = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 25}

x = \frac{- 40}{2 \cdot 25}

\frac{- 40}{2 \cdot 25} = - \frac{4}{5}

x = - \frac{4}{5}

The solution to the quadratic equation is:

x = - \frac{4}{5}

x^{3} - x^{2} - 72 x

(x) (x)

6 g - 18 h

50 - 2 y^{2}

What are the solutions to the equation 25x^2+16=-40x ?
The solutions to the equation 25x^2+16=-40x are x=-4/5
Find the zeros of 25x^2+16=-40x
The zeros of 25x^2+16=-40x are x=-4/5