What are the solutions to the equation 11=(7+2x)^2 ?

The solutions to the equation 11=(7+2x)^2 are x=(sqrt(11)-7)/2 ,x=(-sqrt(11)-7)/2

Find the zeros of 11=(7+2x)^2

The zeros of 11=(7+2x)^2 are x=(sqrt(11)-7)/2 ,x=(-sqrt(11)-7)/2

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11 = (7 + 2 x)^{2}

x = \frac{11 - 7}{2}, x = \frac{- 11 - 7}{2}

Decimal Notation

x = - 1.84168 \dots, x = - 5.15831 \dots

Solution steps

11 = (7 + 2 x)^{2}

Switch sides

(7 + 2 x)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 + 2 x = 11 : x = \frac{11 - 7}{2}

Solve

7 + 2 x = - 11 : x = \frac{- 11 - 7}{2}

The solutions to the quadratic equation are:

x = \frac{11 - 7}{2}, x = \frac{- 11 - 7}{2}

0.165 + 1

- 3 (1)^{2}

- 3 b - 4 \leq - 3 b - 4 \leq 3 b + 33 b + 3

∣ 26 - 4 c ∣ = - 2

2 - 2 x > - 20

What are the solutions to the equation 11=(7+2x)^2 ?
The solutions to the equation 11=(7+2x)^2 are x=(sqrt(11)-7)/2 ,x=(-sqrt(11)-7)/2
Find the zeros of 11=(7+2x)^2
The zeros of 11=(7+2x)^2 are x=(sqrt(11)-7)/2 ,x=(-sqrt(11)-7)/2