What is (3x+5)/(x^2+2x-35)>= 0 ?

The solution to (3x+5)/(x^2+2x-35)>= 0 is -7 5

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(3x+5)/(x^2+2x-35)>= 0

\frac{3 x + 5}{x ^{2} + 2 x - 35} \geq 0

- 7 < x \leq - \frac{5}{3} or x > 5

Interval Notation

(- 7, - \frac{5}{3}] \cup (5, \infty)

Decimal Notation

- 7 < x \leq - 1.66666 \dots or x > 5

Solution steps

\frac{3 x + 5}{x ^{2} + 2 x - 35} \geq 0

Factor

\frac{3 x + 5}{x ^{2} + 2 x - 35} : \frac{3 x + 5}{( x - 5 ) ( x + 7 )}

\frac{3 x + 5}{( x - 5 ) ( x + 7 )} \geq 0

Identify the intervals

- 7 < x \leq - \frac{5}{3} or x > 5

\frac{1 - ( 2 ) ^{2}}{( 1 + ( 2 ) ^{2} ) ^{2}}

9 x^{2} - 3 x - 6

\frac{1}{5} \cdot \frac{1}{5}

x^{2} + 10 x y + 24 y^{2}

4^{x + 3} < 256

What is (3x+5)/(x^2+2x-35)>= 0 ?
The solution to (3x+5)/(x^2+2x-35)>= 0 is -7<x<=-5/3 \lor x>5