What are the solutions to the equation 2x^2+13x-99=0 ?

The solutions to the equation 2x^2+13x-99=0 are x= 9/2 ,x=-11

Find the zeros of 2x^2+13x-99=0

The zeros of 2x^2+13x-99=0 are x= 9/2 ,x=-11

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2 x^{2} + 13 x - 99 = 0

x = \frac{9}{2}, x = - 11

Decimal Notation

x = 4.5, x = - 11

Solution steps

2 x^{2} + 13 x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 99 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 99) = 31

x_{1, 2} = \frac{- 13 \pm 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 31}{2 \cdot 2}, x_{2} = \frac{- 13 - 31}{2 \cdot 2}

x = \frac{- 13 + 31}{2 \cdot 2} : \frac{9}{2}

x = \frac{- 13 - 31}{2 \cdot 2} : - 11

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 11

\frac{( - 3 ) ^{0}}{( - 3 ) ^{2}}

\frac{4}{6} \cdot \frac{3}{8}

x^{3} - 2 x^{2}

- 13 \geq \frac{1}{4} r - 16

196

What are the solutions to the equation 2x^2+13x-99=0 ?
The solutions to the equation 2x^2+13x-99=0 are x= 9/2 ,x=-11
Find the zeros of 2x^2+13x-99=0
The zeros of 2x^2+13x-99=0 are x= 9/2 ,x=-11