What is factor z^2+4z-12 ?

The solution to factor z^2+4z-12 is (z-2)(z+6)

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factor z^2+4z-12

factor

z^{2} + 4 z - 12

(z - 2) (z + 6)

Solution steps

z^{2} + 4 z - 12

Break the expression into groups

= (z^{2} - 2 z) + (6 z - 12)

Factor out

z

from

z^{2} - 2 z : z (z - 2)

Factor out

6

from

6 z - 12 : 6 (z - 2)

= z (z - 2) + 6 (z - 2)

Factor out common term

z - 2

= (z - 2) (z + 6)

5 k + 3 = k - 17

15 a x + 20 a y

\frac{4 !}{( 4 - 2 ) ! \cdot 2 !}

- 5 (- x - 3) - x + 2 = 1

1250 p^{7} q - 32 p^{3} q^{5}