What are the solutions to the equation m^2+9m+20=0 ?

The solutions to the equation m^2+9m+20=0 are m=-4,m=-5

Find the zeros of m^2+9m+20=0

The zeros of m^2+9m+20=0 are m=-4,m=-5

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m^{2} + 9 m + 20 = 0

m = - 4, m = - 5

Solution steps

m^{2} + 9 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

m_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 9 + 1}{2 \cdot 1}, m_{2} = \frac{- 9 - 1}{2 \cdot 1}

m = \frac{- 9 + 1}{2 \cdot 1} : - 4

m = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

m = - 4, m = - 5

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What are the solutions to the equation m^2+9m+20=0 ?
The solutions to the equation m^2+9m+20=0 are m=-4,m=-5
Find the zeros of m^2+9m+20=0
The zeros of m^2+9m+20=0 are m=-4,m=-5