What is factor b^2-9b+18 ?

The solution to factor b^2-9b+18 is (b-3)(b-6)

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factor b^2-9b+18

factor

b^{2} - 9 b + 18

(b - 3) (b - 6)

Solution steps

b^{2} - 9 b + 18

Break the expression into groups

= (b^{2} - 3 b) + (- 6 b + 18)

Factor out

b

from

b^{2} - 3 b : b (b - 3)

Factor out

- 6

from

- 6 b + 18 : - 6 (b - 3)

= b (b - 3) - 6 (b - 3)

Factor out common term

b - 3

= (b - 3) (b - 6)

x^{2} + 2 x - 24 = 0

3 b + 17 \leq 4 b + 23 + 2 b

(3 x + 2)^{\frac{7}{2}}

\frac{3}{2} ∣ x + 4 ∣ - 2 = \frac{5}{2}

∣ 3 x + 1 ∣ \geq 7