What are the solutions to the equation 1/9 x^2+1/3 x-2=0 ?

The solutions to the equation 1/9 x^2+1/3 x-2=0 are x=3,x=-6

Find the zeros of 1/9 x^2+1/3 x-2=0

The zeros of 1/9 x^2+1/3 x-2=0 are x=3,x=-6

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\frac{1}{9} x^{2} + \frac{1}{3} x - 2 = 0

x = 3, x = - 6

Solution steps

\frac{1}{9} x^{2} + \frac{1}{3} x - 2 = 0

Find Least Common Multiplier of

9, 3 : 9

Multiply by LCM=

9

\frac{1}{9} x^{2} \cdot 9 + \frac{1}{3} x \cdot 9 - 2 \cdot 9 = 0 \cdot 9

Simplify

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

x^{2} + 14 x + 13 = 0

- 10.74 = u - (- 11)

x^{2} - x - \frac{3}{4} = 0

49 + 4

\frac{2 x}{3} - \frac{x}{6} = 20

What are the solutions to the equation 1/9 x^2+1/3 x-2=0 ?
The solutions to the equation 1/9 x^2+1/3 x-2=0 are x=3,x=-6
Find the zeros of 1/9 x^2+1/3 x-2=0
The zeros of 1/9 x^2+1/3 x-2=0 are x=3,x=-6