What are the solutions to the equation x^2-(x/2)^2=3 ?

The solutions to the equation x^2-(x/2)^2=3 are x=2,x=-2

Find the zeros of x^2-(x/2)^2=3

The zeros of x^2-(x/2)^2=3 are x=2,x=-2

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x^{2} - (\frac{x}{2})^{2} = 3

x = 2, x = - 2

Solution steps

x^{2} - (\frac{x}{2})^{2} = 3

Expand

x^{2} - (\frac{x}{2})^{2} : \frac{3 x ^{2}}{4}

\frac{3 x ^{2}}{4} = 3

Move

3

to the left side

\frac{3 x ^{2}}{4} - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot \frac{3}{4} ( - 3 )}{2 \cdot \frac{3}{4}}

0^{2} - 4 \cdot \frac{3}{4} (- 3) = 3

x_{1, 2} = \frac{- 0 \pm 3}{2 \cdot \frac{3}{4}}

Separate the solutions

x_{1} = \frac{- 0 + 3}{2 \cdot \frac{3}{4}}, x_{2} = \frac{- 0 - 3}{2 \cdot \frac{3}{4}}

x = \frac{- 0 + 3}{2 \frac{3}{4}} : 2

x = \frac{- 0 - 3}{2 \frac{3}{4}} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

15 x^{2} + 34 x + 15

10 x^{2} + 17 x + 3 = 0

x^{2} + 6 x + 10 = 0

\frac{3 x}{2} - \frac{4 x}{5} + \frac{x}{6} = 0

- 9 x \geq 63

What are the solutions to the equation x^2-(x/2)^2=3 ?
The solutions to the equation x^2-(x/2)^2=3 are x=2,x=-2
Find the zeros of x^2-(x/2)^2=3
The zeros of x^2-(x/2)^2=3 are x=2,x=-2