What are the solutions to the equation 4x^2+8x=5 ?

The solutions to the equation 4x^2+8x=5 are x= 1/2 ,x=-5/2

Find the zeros of 4x^2+8x=5

The zeros of 4x^2+8x=5 are x= 1/2 ,x=-5/2

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4 x^{2} + 8 x = 5

x = \frac{1}{2}, x = - \frac{5}{2}

Decimal Notation

x = 0.5, x = - 2.5

Solution steps

4 x^{2} + 8 x = 5

Move

5

to the left side

4 x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 5) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 4}, x_{2} = \frac{- 8 - 12}{2 \cdot 4}

x = \frac{- 8 + 12}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 8 - 12}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{2}

x - 13 < - 11

x^{3} \geq x

\frac{y}{3} + \frac{y}{5} = 8

- 5 (- 2 - 8 m) = 10 + 5 m

6 (6 v + 6) - 5 = 1 + 6 v

What are the solutions to the equation 4x^2+8x=5 ?
The solutions to the equation 4x^2+8x=5 are x= 1/2 ,x=-5/2
Find the zeros of 4x^2+8x=5
The zeros of 4x^2+8x=5 are x= 1/2 ,x=-5/2