What is factor x^4-x^3+2x^2-4x-8 ?

The solution to factor x^4-x^3+2x^2-4x-8 is (x+1)(x-2)(x^2+4)

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factor x^4-x^3+2x^2-4x-8

factor

x^{4} - x^{3} + 2 x^{2} - 4 x - 8

(x + 1) (x - 2) (x^{2} + 4)

Solution steps

x^{4} - x^{3} + 2 x^{2} - 4 x - 8

Use the rational root theorem

= (x + 1) \frac{x ^{4} - x ^{3} + 2 x ^{2} - 4 x - 8}{x + 1}

\frac{x ^{4} - x ^{3} + 2 x ^{2} - 4 x - 8}{x + 1} = x^{3} - 2 x^{2} + 4 x - 8

= (x + 1) (x^{3} - 2 x^{2} + 4 x - 8)

Factor

x^{3} - 2 x^{2} + 4 x - 8 : (x - 2) (x^{2} + 4)

= (x + 1) (x - 2) (x^{2} + 4)

∣ 5 x - 3 ∣ \leq 7

17 m^{3} n^{3} - 51 m^{2} n^{2} + 85 mn

8 w^{2} - 2 v + w v - 16 w

4 (x - 2) - 5 (2 x - 6) = 8 (x + 1) - 3 (2 x + 3)

\frac{64}{3} - 32

What is factor x^4-x^3+2x^2-4x-8 ?
The solution to factor x^4-x^3+2x^2-4x-8 is (x+1)(x-2)(x^2+4)