What are the solutions to the equation (-x)^2+1=0 ?

The solutions to the equation (-x)^2+1=0 are x=-i,x=i

Find the zeros of (-x)^2+1=0

The zeros of (-x)^2+1=0 are x=-i,x=i

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(- x)^{2} + 1 = 0

x = - i, x = i

Solution steps

(- x)^{2} + 1 = 0

Move

1

to the right side

(- x)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- x = - 1 : x = - i

Solve

- x = - - 1 : x = i

The solutions to the quadratic equation are:

x = - i, x = i

(6 - 4 i)^{2}

5 x^{2} - 10 x - 2 = 0

2 (x - 6) = - 5

7 \leq x - 9

- 2 x^{2} + 1 \geq 0

What are the solutions to the equation (-x)^2+1=0 ?
The solutions to the equation (-x)^2+1=0 are x=-i,x=i
Find the zeros of (-x)^2+1=0
The zeros of (-x)^2+1=0 are x=-i,x=i