What are the solutions to the equation (z+1)^2=-9 ?

The solutions to the equation (z+1)^2=-9 are z=3i-1,z=-3i-1

Find the zeros of (z+1)^2=-9

The zeros of (z+1)^2=-9 are z=3i-1,z=-3i-1

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(z + 1)^{2} = - 9

z = 3 i - 1, z = - 3 i - 1

Solution steps

(z + 1)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 1 = - 9 : z = 3 i - 1

Solve

z + 1 = - - 9 : z = - 3 i - 1

The solutions to the quadratic equation are:

z = 3 i - 1, z = - 3 i - 1

\frac{3}{4} - \frac{3}{5}

\frac{- 2}{1 + 3 i}

x^{2} + 3 x + 3 = 0

- \frac{1}{5} x > 3

x^{2} + 16 x - 36 = 0

What are the solutions to the equation (z+1)^2=-9 ?
The solutions to the equation (z+1)^2=-9 are z=3i-1,z=-3i-1
Find the zeros of (z+1)^2=-9
The zeros of (z+1)^2=-9 are z=3i-1,z=-3i-1