What are the solutions to the equation 3x^2-27x+54=0 ?

The solutions to the equation 3x^2-27x+54=0 are x=6,x=3

Find the zeros of 3x^2-27x+54=0

The zeros of 3x^2-27x+54=0 are x=6,x=3

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3 x^{2} - 27 x + 54 = 0

x = 6, x = 3

Solution steps

3 x^{2} - 27 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 3 \cdot 54}{2 \cdot 3}

(- 27)^{2} - 4 \cdot 3 \cdot 54 = 9

x_{1, 2} = \frac{- ( - 27 ) \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 9}{2 \cdot 3}, x_{2} = \frac{- ( - 27 ) - 9}{2 \cdot 3}

x = \frac{- ( - 27 ) + 9}{2 \cdot 3} : 6

x = \frac{- ( - 27 ) - 9}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

v + \frac{5}{8} = \frac{1}{4}

(8 - 9 a) a = - 40 + (6 - 3 a) (6 + 3 a)

2 (- 4)

5 a - ab

\frac{3 6}{2}

What are the solutions to the equation 3x^2-27x+54=0 ?
The solutions to the equation 3x^2-27x+54=0 are x=6,x=3
Find the zeros of 3x^2-27x+54=0
The zeros of 3x^2-27x+54=0 are x=6,x=3