What is ((3x^4)/(4x^2))^2 ?

The solution to ((3x^4)/(4x^2))^2 is (9x^4)/(16)

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simplify ((3x^4)/(4x^2))^2

simplify

(\frac{3 x ^{4}}{4 x ^{2}})^{2}

\frac{9 x ^{4}}{16}

Solution steps

(\frac{3 x ^{4}}{4 x ^{2}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 x ^{4} ) ^{2}}{( 4 x ^{2} ) ^{2}}

Simplify

(3 x^{4})^{2} : 9 x^{8}

= \frac{9 x ^{8}}{( 4 x ^{2} ) ^{2}}

Simplify

(4 x^{2})^{2} : 16 x^{4}

= \frac{9 x ^{8}}{16 x ^{4}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{8}}{x ^{4}} = x^{8 - 4}

= \frac{9 x ^{8 - 4}}{16}

Subtract the numbers:

8 - 4 = 4

= \frac{9 x ^{4}}{16}

\frac{( 2 - 6 )}{4}

r^{2} - 3 r + 2

- 3 < 6 - 3 x \leq - 1

\frac{x ^{9}}{x ^{5}}