What is factor 9u^2+24u+16 ?

The solution to factor 9u^2+24u+16 is (3u+4)^2

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factor 9u^2+24u+16

factor

9 u^{2} + 24 u + 16

(3 u + 4)^{2}

Solution steps

9 u^{2} + 24 u + 16

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

9 u^{2} = (3 u)^{2}

16 = 4^{2}

24 u = 2 \cdot 3 u \cdot 4

= (3 u)^{2} + 2 \cdot 3 u \cdot 4 + 4^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(3 u)^{2} + 2 \cdot 3 u \cdot 4 + 4^{2} = (3 u + 4)^{2}

= (3 u + 4)^{2}

12 < 4 x < 24

w^{3} - 125

\frac{( 2 - 2 i )}{( 1 + i )}

\frac{- 4. 5 ^{2}}{5} + 2 \cdot 4.5

6 x^{2} - 18 x - 108