What are the solutions to the equation 10x^2+x-2=0 ?

The solutions to the equation 10x^2+x-2=0 are x= 2/5 ,x=-1/2

Find the zeros of 10x^2+x-2=0

The zeros of 10x^2+x-2=0 are x= 2/5 ,x=-1/2

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10 x^{2} + x - 2 = 0

x = \frac{2}{5}, x = - \frac{1}{2}

Decimal Notation

x = 0.4, x = - 0.5

Solution steps

10 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

1^{2} - 4 \cdot 10 (- 2) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 10}, x_{2} = \frac{- 1 - 9}{2 \cdot 10}

x = \frac{- 1 + 9}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 1 - 9}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{2}

5 + 3 x = 11

(x - 12)^{2} = 16

- 16 t^{2} + 80 t = 32

∣ w ∣ \geq 5

(- 6 a^{2} b) \cdot (\frac{1}{2} ab)

What are the solutions to the equation 10x^2+x-2=0 ?
The solutions to the equation 10x^2+x-2=0 are x= 2/5 ,x=-1/2
Find the zeros of 10x^2+x-2=0
The zeros of 10x^2+x-2=0 are x= 2/5 ,x=-1/2