What are the solutions to the equation x^2+8x=9 ?

The solutions to the equation x^2+8x=9 are x=1,x=-9

Find the zeros of x^2+8x=9

The zeros of x^2+8x=9 are x=1,x=-9

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x^{2} + 8 x = 9

x = 1, x = - 9

Solution steps

x^{2} + 8 x = 9

Move

9

to the left side

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

- 3 z^{2} - 2 z + 4 = 0

5 + 4 x + (- 3) = - 10

- 5 \leq x < 2

\frac{x}{5} = 2 x - 6

x^{- 7}

What are the solutions to the equation x^2+8x=9 ?
The solutions to the equation x^2+8x=9 are x=1,x=-9
Find the zeros of x^2+8x=9
The zeros of x^2+8x=9 are x=1,x=-9