What are the solutions to the equation 15x^2-17x-4=0 ?

The solutions to the equation 15x^2-17x-4=0 are x= 4/3 ,x=-1/5

Find the zeros of 15x^2-17x-4=0

The zeros of 15x^2-17x-4=0 are x= 4/3 ,x=-1/5

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15 x^{2} - 17 x - 4 = 0

x = \frac{4}{3}, x = - \frac{1}{5}

Decimal Notation

x = 1.33333 \dots, x = - 0.2

Solution steps

15 x^{2} - 17 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 15 ( - 4 )}{2 \cdot 15}

(- 17)^{2} - 4 \cdot 15 (- 4) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 15}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 15}

x = \frac{- ( - 17 ) + 23}{2 \cdot 15} : \frac{4}{3}

x = \frac{- ( - 17 ) - 23}{2 \cdot 15} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{1}{5}

lo g_{3} (100)

\frac{x - 6}{x + 8} > 0

x^{2} - 60 x + 210 = 0

(2 x - 3)^{2}

225 \cdot \frac{π}{180}

What are the solutions to the equation 15x^2-17x-4=0 ?
The solutions to the equation 15x^2-17x-4=0 are x= 4/3 ,x=-1/5
Find the zeros of 15x^2-17x-4=0
The zeros of 15x^2-17x-4=0 are x= 4/3 ,x=-1/5