What are the solutions to the equation (q)(11q+4)=0 ?

The solutions to the equation (q)(11q+4)=0 are q=0,q=-4/11

Find the zeros of (q)(11q+4)=0

The zeros of (q)(11q+4)=0 are q=0,q=-4/11

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(q) (11 q + 4) = 0

q = 0, q = - \frac{4}{11}

Decimal Notation

q = 0, q = - 0.36363 \dots

Solution steps

(q) (11 q + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

q = 0 or 11 q + 4 = 0

Solve

11 q + 4 = 0 : q = - \frac{4}{11}

The solutions to the quadratic equation are:

q = 0, q = - \frac{4}{11}

26 = - 12 v - 9 + 7 v

\frac{1}{6} \cdot 9

10 m^{2} n + 30 m n^{2} + 5 mn

2 - 4 x = 14

- 4 - \frac{x}{3} = - 8

What are the solutions to the equation (q)(11q+4)=0 ?
The solutions to the equation (q)(11q+4)=0 are q=0,q=-4/11
Find the zeros of (q)(11q+4)=0
The zeros of (q)(11q+4)=0 are q=0,q=-4/11