What are the solutions to the equation -x^2+7x-18=0 ?

The solutions to the equation -x^2+7x-18=0 are x= 7/2-i(sqrt(23))/2 ,x= 7/2+i(sqrt(23))/2

Find the zeros of -x^2+7x-18=0

The zeros of -x^2+7x-18=0 are x= 7/2-i(sqrt(23))/2 ,x= 7/2+i(sqrt(23))/2

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- x^{2} + 7 x - 18 = 0

x = \frac{7}{2} - i \frac{23}{2}, x = \frac{7}{2} + i \frac{23}{2}

Solution steps

- x^{2} + 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

Simplify

7^{2} - 4 (- 1) (- 18) : 23 i

x_{1, 2} = \frac{- 7 \pm 23 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 23 i}{2 ( - 1 )}, x_{2} = \frac{- 7 - 23 i}{2 ( - 1 )}

x = \frac{- 7 + 23 i}{2 ( - 1 )} : \frac{7}{2} - i \frac{23}{2}

x = \frac{- 7 - 23 i}{2 ( - 1 )} : \frac{7}{2} + i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2} - i \frac{23}{2}, x = \frac{7}{2} + i \frac{23}{2}

2 x + 287 - x = 360

lo g_{2} (\frac{1}{128})

\frac{2 - 2 i}{1 + i}

3^{9}

1 - (a + b)^{3}

What are the solutions to the equation -x^2+7x-18=0 ?
The solutions to the equation -x^2+7x-18=0 are x= 7/2-i(sqrt(23))/2 ,x= 7/2+i(sqrt(23))/2
Find the zeros of -x^2+7x-18=0
The zeros of -x^2+7x-18=0 are x= 7/2-i(sqrt(23))/2 ,x= 7/2+i(sqrt(23))/2