What are the solutions to the equation a^2+(-a/7)^2=1 ?

The solutions to the equation a^2+(-a/7)^2=1 are a= 7/(5sqrt(2)),a=-7/(5sqrt(2))

Find the zeros of a^2+(-a/7)^2=1

The zeros of a^2+(-a/7)^2=1 are a= 7/(5sqrt(2)),a=-7/(5sqrt(2))

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a^{2} + (- \frac{a}{7})^{2} = 1

a = \frac{7}{5 2}, a = - \frac{7}{5 2}

Decimal Notation

a = 0.98994 \dots, a = - 0.98994 \dots

Solution steps

a^{2} + (- \frac{a}{7})^{2} = 1

Expand

a^{2} + (- \frac{a}{7})^{2} : \frac{50 a ^{2}}{49}

\frac{50 a ^{2}}{49} = 1

Move

1

to the left side

\frac{50 a ^{2}}{49} - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot \frac{50}{49} ( - 1 )}{2 \cdot \frac{50}{49}}

0^{2} - 4 \cdot \frac{50}{49} (- 1) = \frac{10 2}{7}

a_{1, 2} = \frac{- 0 \pm \frac{10 2}{7}}{2 \cdot \frac{50}{49}}

Separate the solutions

a_{1} = \frac{- 0 + \frac{10 2}{7}}{2 \cdot \frac{50}{49}}, a_{2} = \frac{- 0 - \frac{10 2}{7}}{2 \cdot \frac{50}{49}}

a = \frac{- 0 + \frac{10 2}{7}}{2 \frac{50}{49}} : \frac{7}{5 2}

a = \frac{- 0 - \frac{10 2}{7}}{2 \frac{50}{49}} : - \frac{7}{5 2}

The solutions to the quadratic equation are:

a = \frac{7}{5 2}, a = - \frac{7}{5 2}

a^{2} + \frac{10}{7} a + \frac{25}{49} = 0

420

3 k^{2} + 10 k + 7

lo g_{1} (2)

350 \cdot 46 = n

What are the solutions to the equation a^2+(-a/7)^2=1 ?
The solutions to the equation a^2+(-a/7)^2=1 are a= 7/(5sqrt(2)),a=-7/(5sqrt(2))
Find the zeros of a^2+(-a/7)^2=1
The zeros of a^2+(-a/7)^2=1 are a= 7/(5sqrt(2)),a=-7/(5sqrt(2))