What are the solutions to the equation 0=-6p^2+12000p ?

The solutions to the equation 0=-6p^2+12000p are p=0,p=2000

Find the zeros of 0=-6p^2+12000p

The zeros of 0=-6p^2+12000p are p=0,p=2000

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0 = - 6 p^{2} + 12000 p

p = 0, p = 2000

Solution steps

0 = - 6 p^{2} + 12000 p

Switch sides

- 6 p^{2} + 12000 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 12000 \pm 1200 0 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

1200 0^{2} - 4 (- 6) \cdot 0 = 12000

p_{1, 2} = \frac{- 12000 \pm 12000}{2 ( - 6 )}

Separate the solutions

p_{1} = \frac{- 12000 + 12000}{2 ( - 6 )}, p_{2} = \frac{- 12000 - 12000}{2 ( - 6 )}

p = \frac{- 12000 + 12000}{2 ( - 6 )} : 0

p = \frac{- 12000 - 12000}{2 ( - 6 )} : 2000

The solutions to the quadratic equation are:

p = 0, p = 2000

827

8 x^{2} + 10 x - 3

17 a x + 17 a - x - 1

3 x - 10 \geq 20

x^{2} - 2 = 2

What are the solutions to the equation 0=-6p^2+12000p ?
The solutions to the equation 0=-6p^2+12000p are p=0,p=2000
Find the zeros of 0=-6p^2+12000p
The zeros of 0=-6p^2+12000p are p=0,p=2000