What are the solutions to the equation x^2+2x+50=0 ?

The solutions to the equation x^2+2x+50=0 are x=-1+7i,x=-1-7i

Find the zeros of x^2+2x+50=0

The zeros of x^2+2x+50=0 are x=-1+7i,x=-1-7i

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x^{2} + 2 x + 50 = 0

x = - 1 + 7 i, x = - 1 - 7 i

Solution steps

x^{2} + 2 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 50 : 14 i

x_{1, 2} = \frac{- 2 \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 14 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 14 i}{2 \cdot 1}

x = \frac{- 2 + 14 i}{2 \cdot 1} : - 1 + 7 i

x = \frac{- 2 - 14 i}{2 \cdot 1} : - 1 - 7 i

The solutions to the quadratic equation are:

x = - 1 + 7 i, x = - 1 - 7 i

\frac{x - 10}{180} + \frac{1}{134} x + \frac{1}{100} x = 0

\frac{x}{2} - \frac{x}{6} = \frac{4}{3}

2 x - 5 = x - 1

\frac{5 + 4 i}{7 + 3 i}

∣ x + 5 ∣ < 2 x - 3

What are the solutions to the equation x^2+2x+50=0 ?
The solutions to the equation x^2+2x+50=0 are x=-1+7i,x=-1-7i
Find the zeros of x^2+2x+50=0
The zeros of x^2+2x+50=0 are x=-1+7i,x=-1-7i