What are the solutions to the equation 2x^2-22=0 ?

The solutions to the equation 2x^2-22=0 are x=sqrt(11),x=-sqrt(11)

Find the zeros of 2x^2-22=0

The zeros of 2x^2-22=0 are x=sqrt(11),x=-sqrt(11)

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2 x^{2} - 22 = 0

x = 11, x = - 11

Decimal Notation

x = 3.31662 \dots, x = - 3.31662 \dots

Solution steps

2 x^{2} - 22 = 0

Move

22

to the right side

2 x^{2} = 22

Divide both sides by

2

x^{2} = 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 11, x = - 11

\frac{x}{3} = - 8

x - 14.4 = 4.4

∣ 3 x + 3 ∣ \geq 6

8 = \frac{3}{5} (7 x + 25)

a^{2} = - 2

What are the solutions to the equation 2x^2-22=0 ?
The solutions to the equation 2x^2-22=0 are x=sqrt(11),x=-sqrt(11)
Find the zeros of 2x^2-22=0
The zeros of 2x^2-22=0 are x=sqrt(11),x=-sqrt(11)