What are the solutions to the equation x^2-4x+14=0 ?

The solutions to the equation x^2-4x+14=0 are x=2+sqrt(10)i,x=2-sqrt(10)i

Find the zeros of x^2-4x+14=0

The zeros of x^2-4x+14=0 are x=2+sqrt(10)i,x=2-sqrt(10)i

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x^{2} - 4 x + 14 = 0

x = 2 + 10 i, x = 2 - 10 i

Solution steps

x^{2} - 4 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 14 : 210 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 10 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 10 i}{2 \cdot 1} : 2 + 10 i

x = \frac{- ( - 4 ) - 2 10 i}{2 \cdot 1} : 2 - 10 i

The solutions to the quadratic equation are:

x = 2 + 10 i, x = 2 - 10 i

x^{3} - 9 x^{2} + 28 x - 30

- 2 x + 2 \leq - 6

\frac{x}{3} - \frac{3}{4} = \frac{3 x + 2}{12}

\frac{14 x ^{4} y ^{7}}{6 x ^{5} y ^{4}}

2 - 4 x < 22

What are the solutions to the equation x^2-4x+14=0 ?
The solutions to the equation x^2-4x+14=0 are x=2+sqrt(10)i,x=2-sqrt(10)i
Find the zeros of x^2-4x+14=0
The zeros of x^2-4x+14=0 are x=2+sqrt(10)i,x=2-sqrt(10)i