What are the solutions to the equation (9x-5)^2=25 ?

The solutions to the equation (9x-5)^2=25 are x= 10/9 ,x=0

Find the zeros of (9x-5)^2=25

The zeros of (9x-5)^2=25 are x= 10/9 ,x=0

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(9 x - 5)^{2} = 25

x = \frac{10}{9}, x = 0

Decimal Notation

x = 1.11111 \dots, x = 0

Solution steps

(9 x - 5)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

9 x - 5 = 25 : x = \frac{10}{9}

Solve

9 x - 5 = - 25 : x = 0

The solutions to the quadratic equation are:

x = \frac{10}{9}, x = 0

m^{2} + 18 m + 56

4 < x \leq 12

x (1 - x) \leq \frac{1}{4}

5 x + 2 x + 20 = 48

9 w - 4 w + 6 \geq 1 + 5 w

What are the solutions to the equation (9x-5)^2=25 ?
The solutions to the equation (9x-5)^2=25 are x= 10/9 ,x=0
Find the zeros of (9x-5)^2=25
The zeros of (9x-5)^2=25 are x= 10/9 ,x=0