What are the solutions to the equation 6x^2+6x-12x=1 ?

The solutions to the equation 6x^2+6x-12x=1 are x=(3+sqrt(15))/6 ,x=(3-sqrt(15))/6

Find the zeros of 6x^2+6x-12x=1

The zeros of 6x^2+6x-12x=1 are x=(3+sqrt(15))/6 ,x=(3-sqrt(15))/6

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6 x^{2} + 6 x - 12 x = 1

x = \frac{3 + 15}{6}, x = \frac{3 - 15}{6}

Decimal Notation

x = 1.14549 \dots, x = - 0.14549 \dots

Solution steps

6 x^{2} + 6 x - 12 x = 1

Refine

6 x^{2} - 6 x = 1

Move

1

to the left side

6 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 6)^{2} - 4 \cdot 6 (- 1) = 215

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15}{2 \cdot 6}, x_{2} = \frac{- ( - 6 ) - 2 15}{2 \cdot 6}

x = \frac{- ( - 6 ) + 2 15}{2 \cdot 6} : \frac{3 + 15}{6}

x = \frac{- ( - 6 ) - 2 15}{2 \cdot 6} : \frac{3 - 15}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 15}{6}, x = \frac{3 - 15}{6}

∣ x - 8 ∣ < - 1

4 x^{2} - (x + y)^{2}

10 x^{2} - 56 = 88 - 6 x^{2}

(\frac{1}{2 x + 1})^{2}

x^{2} + 5 x + 8 = 0

What are the solutions to the equation 6x^2+6x-12x=1 ?
The solutions to the equation 6x^2+6x-12x=1 are x=(3+sqrt(15))/6 ,x=(3-sqrt(15))/6
Find the zeros of 6x^2+6x-12x=1
The zeros of 6x^2+6x-12x=1 are x=(3+sqrt(15))/6 ,x=(3-sqrt(15))/6