What are the solutions to the equation -x^2-5=0 ?

The solutions to the equation -x^2-5=0 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of -x^2-5=0

The zeros of -x^2-5=0 are x=sqrt(5)i,x=-sqrt(5)i

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- x^{2} - 5 = 0

x = 5 i, x = - 5 i

Solution steps

- x^{2} - 5 = 0

Move

5

to the right side

- x^{2} = 5

Divide both sides by

- 1

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

\frac{- 3 ( v ^{3} ) ^{- 5}}{6 s ^{- 7}}

4 A + 2 = A + 5

4 x^{2} - 16 x + 16

2 = - \frac{2}{3} (4) + b

k^{2} - j^{2}

What are the solutions to the equation -x^2-5=0 ?
The solutions to the equation -x^2-5=0 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of -x^2-5=0
The zeros of -x^2-5=0 are x=sqrt(5)i,x=-sqrt(5)i