What are the solutions to the equation 3x^2+3x-4=0 ?

The solutions to the equation 3x^2+3x-4=0 are x=(-3+sqrt(57))/6 ,x=(-3-sqrt(57))/6

Find the zeros of 3x^2+3x-4=0

The zeros of 3x^2+3x-4=0 are x=(-3+sqrt(57))/6 ,x=(-3-sqrt(57))/6

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3 x^{2} + 3 x - 4 = 0

x = \frac{- 3 + 57}{6}, x = \frac{- 3 - 57}{6}

Decimal Notation

x = 0.75830 \dots, x = - 1.75830 \dots

Solution steps

3 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 4) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 3}, x_{2} = \frac{- 3 - 57}{2 \cdot 3}

x = \frac{- 3 + 57}{2 \cdot 3} : \frac{- 3 + 57}{6}

x = \frac{- 3 - 57}{2 \cdot 3} : \frac{- 3 - 57}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{6}, x = \frac{- 3 - 57}{6}

3 x^{2} + 5 x + 1 = 0

x^{2} - 8 x = 10

x^{2} - 8 x + 40 = 0

18 m^{2} + 12 m + 1997 = 0

\frac{50}{4} - \frac{165}{2}

What are the solutions to the equation 3x^2+3x-4=0 ?
The solutions to the equation 3x^2+3x-4=0 are x=(-3+sqrt(57))/6 ,x=(-3-sqrt(57))/6
Find the zeros of 3x^2+3x-4=0
The zeros of 3x^2+3x-4=0 are x=(-3+sqrt(57))/6 ,x=(-3-sqrt(57))/6