What are the solutions to the equation (2x-1)^2=25 ?

The solutions to the equation (2x-1)^2=25 are x=3,x=-2

Find the zeros of (2x-1)^2=25

The zeros of (2x-1)^2=25 are x=3,x=-2

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(2 x - 1)^{2} = 25

x = 3, x = - 2

Solution steps

(2 x - 1)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 25 : x = 3

Solve

2 x - 1 = - 25 : x = - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

54 + 3 z - z^{2}

2 x^{2} - 13 x + 21

(x + 7)^{2} (x + 5) (x - 1) > 0

\frac{2}{3} x - 2 < 2 x - 3 < 6 + \frac{2}{3} x

\frac{x}{9} + \frac{1}{3} = \frac{1}{18}

What are the solutions to the equation (2x-1)^2=25 ?
The solutions to the equation (2x-1)^2=25 are x=3,x=-2
Find the zeros of (2x-1)^2=25
The zeros of (2x-1)^2=25 are x=3,x=-2