What is the answer to |x+2|=sqrt(4-x) ?

The answer to |x+2|=sqrt(4-x) is x=-5\lor x=0

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|x+2|=sqrt(4-x)

∣ x + 2 ∣ = 4 - x

x = - 5 or x = 0

Solution steps

∣ x + 2 ∣ = 4 - x

Find positive and negative intervals

x < - 2, x \geq - 2

Solve the inequality for each interval

x = - 5 or x = 0

\frac{2 x - 3}{x + 1} + 2 > 0

2 x + 9 + 3 x + x = 5 x + 2

3 x^{2} - 24 x + 45

2 x (3 - 4 x) - \frac{x - 2}{5} = \frac{1}{2} [x + 3 - \frac{x - 1}{2}]

(3^{5})^{2}

What is the answer to |x+2|=sqrt(4-x) ?
The answer to |x+2|=sqrt(4-x) is x=-5\lor x=0
Solve for x: |x+2|=sqrt(4-x)
The solution is x=-5\lor x=0