What are the solutions to the equation 7y^2+18=4 ?

The solutions to the equation 7y^2+18=4 are y=sqrt(2)i,y=-sqrt(2)i

Find the zeros of 7y^2+18=4

The zeros of 7y^2+18=4 are y=sqrt(2)i,y=-sqrt(2)i

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7 y^{2} + 18 = 4

y = 2 i, y = - 2 i

Solution steps

7 y^{2} + 18 = 4

Move

18

to the right side

7 y^{2} = - 14

Divide both sides by

7

y^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 2, y = - - 2

- 2 = 2 i

- - 2 = - 2 i

y = 2 i, y = - 2 i

6 b - 1 < - 7

\frac{3}{7} \cdot 14 + \frac{5}{8} \cdot 8

7 - \frac{x}{12} = 9

x^{3} y^{3} + y^{4}

2 n + 8 > 12

What are the solutions to the equation 7y^2+18=4 ?
The solutions to the equation 7y^2+18=4 are y=sqrt(2)i,y=-sqrt(2)i
Find the zeros of 7y^2+18=4
The zeros of 7y^2+18=4 are y=sqrt(2)i,y=-sqrt(2)i