What are the solutions to the equation m^2-11m+18=0 ?

The solutions to the equation m^2-11m+18=0 are m=9,m=2

Find the zeros of m^2-11m+18=0

The zeros of m^2-11m+18=0 are m=9,m=2

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m^{2} - 11 m + 18 = 0

m = 9, m = 2

Solution steps

m^{2} - 11 m + 18 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 18 = 7

m_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 1}, m_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 1}

m = \frac{- ( - 11 ) + 7}{2 \cdot 1} : 9

m = \frac{- ( - 11 ) - 7}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

m = 9, m = 2

∣ x ∣ + 3 \geq 0

5 (x - 1) \geq 5 x - 6

- 3 x - 7 > \frac{x}{2}

r^{2} + 2 r - 3 = 0

- 7 z - 7 \leq - 5 z + 5

What are the solutions to the equation m^2-11m+18=0 ?
The solutions to the equation m^2-11m+18=0 are m=9,m=2
Find the zeros of m^2-11m+18=0
The zeros of m^2-11m+18=0 are m=9,m=2