What are the solutions to the equation (x-1)^2-7=23 ?

The solutions to the equation (x-1)^2-7=23 are x=sqrt(30)+1,x=-sqrt(30)+1

Find the zeros of (x-1)^2-7=23

The zeros of (x-1)^2-7=23 are x=sqrt(30)+1,x=-sqrt(30)+1

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(x - 1)^{2} - 7 = 23

x = 30 + 1, x = - 30 + 1

Decimal Notation

x = 6.47722 \dots, x = - 4.47722 \dots

Solution steps

(x - 1)^{2} - 7 = 23

Move

7

to the right side

(x - 1)^{2} = 30

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 30 : x = 30 + 1

Solve

x - 1 = - 30 : x = - 30 + 1

The solutions to the quadratic equation are:

x = 30 + 1, x = - 30 + 1

v^{4} - 625

0.065 = x (\frac{0.63 ( 0.37 )}{100})

3 v - v = 4

- \frac{9}{13} - \frac{1}{2}

2 x^{2} - a x^{2} + a y - 2 y

What are the solutions to the equation (x-1)^2-7=23 ?
The solutions to the equation (x-1)^2-7=23 are x=sqrt(30)+1,x=-sqrt(30)+1
Find the zeros of (x-1)^2-7=23
The zeros of (x-1)^2-7=23 are x=sqrt(30)+1,x=-sqrt(30)+1