What are the solutions to the equation x^2+6x+2=0 ?

The solutions to the equation x^2+6x+2=0 are x=-3+sqrt(7),x=-3-sqrt(7)

Find the zeros of x^2+6x+2=0

The zeros of x^2+6x+2=0 are x=-3+sqrt(7),x=-3-sqrt(7)

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x^{2} + 6 x + 2 = 0

x = - 3 + 7, x = - 3 - 7

Decimal Notation

x = - 0.35424 \dots, x = - 5.64575 \dots

Solution steps

x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 2 = 27

x_{1, 2} = \frac{- 6 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 7}{2 \cdot 1}

x = \frac{- 6 + 2 7}{2 \cdot 1} : - 3 + 7

x = \frac{- 6 - 2 7}{2 \cdot 1} : - 3 - 7

The solutions to the quadratic equation are:

x = - 3 + 7, x = - 3 - 7

∣ x - 4 ∣ = 1

\frac{a}{2} - 1 \geq 1

3 m > 24

3 y + 5 < 10

8 k^{2} - 10 k + 3

What are the solutions to the equation x^2+6x+2=0 ?
The solutions to the equation x^2+6x+2=0 are x=-3+sqrt(7),x=-3-sqrt(7)
Find the zeros of x^2+6x+2=0
The zeros of x^2+6x+2=0 are x=-3+sqrt(7),x=-3-sqrt(7)