What are the solutions to the equation 7x-5+12x^2=-3x ?

The solutions to the equation 7x-5+12x^2=-3x are x=(-5+sqrt(85))/(12),x=-(5+sqrt(85))/(12)

Find the zeros of 7x-5+12x^2=-3x

The zeros of 7x-5+12x^2=-3x are x=(-5+sqrt(85))/(12),x=-(5+sqrt(85))/(12)

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7 x - 5 + 12 x^{2} = - 3 x

x = \frac{- 5 + 85}{12}, x = - \frac{5 + 85}{12}

Decimal Notation

x = 0.35162 \dots, x = - 1.18496 \dots

Solution steps

7 x - 5 + 12 x^{2} = - 3 x

Move

3 x

to the left side

12 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

1 0^{2} - 4 \cdot 12 (- 5) = 285

x_{1, 2} = \frac{- 10 \pm 2 85}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 10 + 2 85}{2 \cdot 12}, x_{2} = \frac{- 10 - 2 85}{2 \cdot 12}

x = \frac{- 10 + 2 85}{2 \cdot 12} : \frac{- 5 + 85}{12}

x = \frac{- 10 - 2 85}{2 \cdot 12} : - \frac{5 + 85}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 85}{12}, x = - \frac{5 + 85}{12}

6 x - 3 x^{2} = 0

- 4 x = 28

x^{2} + 3 x - 10 \leq 0

- (\frac{1}{3})^{- 1}

3 x - 6 = 6

What are the solutions to the equation 7x-5+12x^2=-3x ?
The solutions to the equation 7x-5+12x^2=-3x are x=(-5+sqrt(85))/(12),x=-(5+sqrt(85))/(12)
Find the zeros of 7x-5+12x^2=-3x
The zeros of 7x-5+12x^2=-3x are x=(-5+sqrt(85))/(12),x=-(5+sqrt(85))/(12)